# Line slope calculator 4x-3y=13

**Straight line given by points A[4; 1] and B[7; 5]**

## Calculation:

**Slope-intercept form of line:**y = 1.3333x-4.3333

**Canonical form of the line equation:**4x-3y-13 = 0

**Parametric form of the line equation:**

x = 3t+4

y = 4t+1 ; t ∈ R

**Slope:**m = 1.3333

**Slope angle of line: φ =**53°7'48″ = 0.9273 rad

**X intercept:**x

_{0}= 3.25

**Y intercept:**y

_{0}= q = -4.3333

**Distance line from the origin:**d

_{0}= 2.6

**The length of the segment AB: |AB| =**5

**Vector: AB =**(3; 4)

**Normal vector: n =**(4; -3)

**Midpoint of the segment AB: M =**[5.5; 3]

**Perpendicular Bisector equation:**3x+4y-28.5 = 0

**Vector OA = (4; 1) ; |OA| = 4.1231**

**Vector OB = (7; 5) ; |OB| = 8.6023**

**Scalar product OA .OB = 33**

**Angle ∠ AOB = 21°30'5″ = 0.3753 rad**